College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Test - Page 167: 8

Answer

$$x=4$$

Work Step by Step

$$\sqrt{3x+4}+5=2x+1$$ $$\sqrt{3x+4}=2x-4$$ $$3x+4=4x^2-16x+16$$ $$0=4x^2-19x+12$$ $$0=(x-4)(4x-3)$$ $$x-4=0$$ $$x=4$$ $$4x-3=0$$ $$x=\frac{3}{4}$$ $\frac{3}{4}$ is an extraneous solution, so $x=4$.
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