College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Test - Page 167: 6

Answer

No solution.

Work Step by Step

$$\frac{12}{(x+3)(x-3)}-\frac{3}{x+3}=\frac{2}{x-3}$$ $$((x+3)(x-3))(\frac{12}{(x+3)(x-3)}-\frac{3}{x+3})=((x+3)(x-3))(\frac{2}{x-3})$$ $$12-3(x-3)=2(x+3)$$ $$12-3x+9=2x+6$$ $$21-3x=2x+6$$ $$15=5x$$ $$x=3$$ 3 is an extraneous solution; there is no solution.
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