Answer
See below.
Work Step by Step
Our equation is: $450=1000(1-e^{-0.15d})\\0.45=1-e^{-0.15d}\\0.55=e^{-0.15d}\\\ln{0.55}=-0.15d\\d=\ln{0.55}\frac{1}{-0.15}\approx3.99$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 451: 126
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