College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 451: 122

Answer

See below.

Work Step by Step

a) Our equation is: $0.5A_0=A_0e^{-0.35n}\\0.5=e^{-0.35n}\\\ln{0.5}=-0.35n\\n=\ln{0.5}\frac{1}{-0.35}\approx1.98$ b) Our equation is: $0.1A_0=A_0e^{-0.35n}\\0.1=e^{-0.35n}\\\ln{0.1}=-0.35n\\n=\ln{0.1}\frac{1}{-0.35}\approx6.58$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.