College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 5 - Section 5.6 - Complex Numbers; Quadratic Equations in the Complex Number System - 5.6 Assess Your Understanding - Page 395: 52

Answer

Area = $9\pi \approx 28.27433$ square feet Circumference = $9\pi \approx 28.27433$ feet

Work Step by Step

RECALL: (1) The area $A$ of a circle is given by the formula $A=\pi{(\frac{d}{2})^2}$ where $d$ = diameter (2) The circumference $C$ of a circle is given by the formula $C=\pi{d}$ where $d$ = diameter. Use the formula in (1) above to obtain the area of the circle: $A=\pi(\frac{6}{2})^2 \\A=\pi(3^2) \\A=\pi(9) \\A=9\pi \approx 28.27433$ Thus, the area of the circle is $9\pi$ or approximately $28.27433$ square feet, Use the formula in (2) above to obtain the circumference of the circle: $C=\pi{d} \\C=\pi(9) \\C=9\pi$ Thus, the circumference of the circle is $9\pi$ or approximately $28.27433$ feet.
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