College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 5 - Section 5.6 - Complex Numbers; Quadratic Equations in the Complex Number System - 5.6 Assess Your Understanding - Page 395: 51

Answer

$6x^3-13x^2-13x+20$

Work Step by Step

Multiply each term of the binomial to trinomial to obtain: $=2x(3x^2+x-4)-5(3x^2+x-4)$ Distribute $2x$ and $-5$ to obtain: $=2x(3x^2) + 2x(x) - 2x(4) - 5(3x^2)-5(x)-5(-4) \\=6x^3+2x^2-8x-15x^2-5x+20$ Combine like terms to obtain: $=6x^3 + (2x^2-15x^2)+(-8x-5x)+20 \\=6x^3-13x^2-13x+20$
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