Answer
$x_1=\dfrac{-4-\sqrt{20}}{-4}$
$x_2=\dfrac{-4+\sqrt{20}}{-4}$
Work Step by Step
We are going to use the quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2(a)}$, where a=-2, b=4, and c=1
$x=\dfrac{-4\pm\sqrt{4^2-4(-2)(1)}}{2(-2)}$
$x=\dfrac{-4\pm\sqrt{16+8}}{-4}$
$x=\dfrac{-4\pm\sqrt{20}}{-4}$
$x_1=\dfrac{-4-\sqrt{20}}{-4}$
$x_2=\dfrac{-4+\sqrt{20}}{-4}$
