College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 4 - Test - Page 318: 2

Answer

The x-intercepts are at $(2, 0)$ and $(-\frac{4}{3}, 0)$. The y-intercept is at $(0, -8)$.

Work Step by Step

To find the x-intercept, you would set f(x) or y = 0: $0 = 3x2 - 2x - 8$ Now, you solve for x. First, factor the equation: $0 = (3x + 4)(x - 2)$ Next, set each factor equal to 0 because for the equation to be equal to zero, one of the factors should be zero: $3x + 4 = 0$ or $x - 2 = 0$ Now you can solve for x: $x = 2$ or $3x = -4$ $x = -\frac{4}{3}$ The x-intercepts are at $(2, 0)$ and $(-\frac{4}{3}, 0)$ To find the y-intercept, you would set x = 0. $y = 3(0)^{2} - 2(0) - 8$ You then simplify this equation: $y = 0 - 0 - 8$ You get as your answer: $y = -8$ The y-intercept is at $(0, -8)$
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