College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.4 - Library of Functions; Piecewise-defined Function - 3.4 Assess Your Understanding - Page 245: 48

Answer

See below.

Work Step by Step

I plug in the values into the function: a) $f(1.2)=int(\frac{1.2}{2})=int(0.6)=0$ b) $f(1.6)=int(\frac{1.6}{2})=int(0.8)=0$ c) $f(-1.8)=int(\frac{-1.8}{2})=int(-0.9)=-1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.