Answer
$a.\quad [-3,\infty)$
$b.\quad (-2.5,0)$, ($0,-3$)
$c.\quad $see image
$d.\quad (-\infty,5)$
$e.\quad $Not continuous (jump at $x=0$)
Work Step by Step
It's best to graph the function first.
For $x\in[-3,0)$
the graph is the line segment on the line $y=2x+5$,
containing points $(-3,-1)$ and $(-1,3)$
The right end of the line segment is marked with an open dot at $(0,5)$.
At $x=0$, the point ($0,-3$) is on the graph. (A jump on the graph - not continuous)
For $x\in(0,\infty)$
the graph is the ray $y=-5x$, with the point $(0,0)$ excluded (open dot)
passing through the point $(1,-5)$
Domain: $[-3,\infty)$
Range : $(-\infty,5)$
x-intercepts:$\quad (-2.5,0)$.
y intercepts:$\quad$ ($0,-3$)
There is a jump on the graph at x=$0$ - not continuous
