College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Test: 7

Answer

$462$

Work Step by Step

RECALL: $C(n, r)= \dfrac{n!}{r!(n-r)!}$ Using the definition above gives: $\require{cancel} C(11, 5)! \\= \dfrac{11!}{5!(11-5)!} \\=\dfrac{11!}{5!6!} \\=\dfrac{11(10)(9)(8)(7)(6!)}{5(4)(3)(2)(1)6!} \\=\dfrac{11(10)(9)\cancel{(8)}(7)\cancel{(6!)}}{5\cancel{(4)}(3)\cancel{(2)}(1)\cancel{6!}} \\=\dfrac{11\cancel{(10)}^2\cancel{(9)}^3(7)}{\cancel{5}\cancel{(3)}(1)} \\=462$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.