College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Test: 6

Answer

$151,200$

Work Step by Step

RECALL: $P(n, r)= \dfrac{n!}{(n-r)!}$ Using the definition above gives: $\require{cancel} P(10, 6)! \\= \dfrac{10!}{(10-6)!} \\=\dfrac{10!}{4!} \\=\dfrac{10(9)(8)(7)(6)(5)\cancel{(4!)}}{\cancel{4!}} \\=151,200$
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