Answer
$151,200$
Work Step by Step
RECALL:
$P(n, r)= \dfrac{n!}{(n-r)!}$
Using the definition above gives:
$\require{cancel}
P(10, 6)!
\\= \dfrac{10!}{(10-6)!}
\\=\dfrac{10!}{4!}
\\=\dfrac{10(9)(8)(7)(6)(5)\cancel{(4!)}}{\cancel{4!}}
\\=151,200$
