College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding: 14

Answer

The solution is $\left\{0\right\}$.

Work Step by Step

Add 1 on both sides of the equation to obtain: $\sqrt[3]{1-2x}-1+1=0+1 \\\sqrt[3]{1-2x}=1$ Cube both sides of the equation to obtain: $1-2x=1^3 \\1-2x=1$ Subtract 1 on both sides to obtain: $-2x = 1-1 \\-2x=0$ Divide -2 to both sides of the equation to obtain: $x=\frac{0}{-2} \\x=0$ Thus, the solution is $\left\{0\right\}$
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