Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set: 56

Answer

$C=8\pi$ in. $A=16\pi$ in.$^2$

Work Step by Step

$C=2\pi r$ $C=2\pi (4)$ $C=8\pi$ $A=\pi r^2$ $A=\pi (4)^2$ $A=16\pi$
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