Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set - Page 665: 46

Answer

$p=kq$

Work Step by Step

Because $p$ varies directly as $q$, we equate $p$ to a constant multiple of $q$: $p=kq$.
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