## Algebra: A Combined Approach (4th Edition)

Answer: $\frac{xz}{2y}$
Given: $\frac{\frac{5x^{2}}{yz^{2}}}{\frac{10x}{z^{3}}}$ $\frac{\frac{5x^{2}}{yz^{2}}}{\frac{10x}{z^{3}}}$ = $\frac{5x^{2}}{yz^{2}}$ $\div$ $\frac{10x}{z^{3}}$ = $\frac{5x^{2}}{yz^{2}}$ $\times$ $\frac{z^{3}}{10x}$ $\frac{5x^{2}}{yz^{2}}$ $\times$ $\frac{z^{3}}{10x}$ = $\frac{5xz}{10y}$ .....( Since $\frac{x^{2}}{x}$ = x and, $\frac{z^{3}}{z^{2}}$ = z) $\frac{5xz}{10y}$ = $\frac{xz}{2y}$ ...(Since $\frac{5}{10}$ = $\frac{1}{2}$)