Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Test - Page 562: 22

Answer

$x = -2$ or $x = 5$

Work Step by Step

$x - \frac{14}{x - 1}$ = $4 - \frac{2x}{x - 1}$ $\frac{x(x - 1) - 14}{(x - 1)}$ = $\frac{4(x - 1) - 2x}{(x - 1)}$ Hence, $x(x - 1) - 14$ = $4(x - 1) - 2x$ $x^2 - x -14 = 4x - 4 - 2x$ $x^2 - 3x - 10 = 0$ $(x + 2)(x - 5) = 0$ $x = -2$ or $x = 5$
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