Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Test: 8

Answer

$\frac{(a+2)}{(a+5)}$

Work Step by Step

$\frac{ay+3a+2y+6}{ay+3a+5y+15}$ =$\frac{a(y+3)+2(y+3)}{a(y+3)+5(y+3)}$ =$\frac{(y+3)(a+2)}{(y+3)(a+5)}$ =$\frac{(a+2)}{(a+5)}$
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