Answer
$\frac{(a+2)}{(a+5)}$
Work Step by Step
$\frac{ay+3a+2y+6}{ay+3a+5y+15}$
=$\frac{a(y+3)+2(y+3)}{a(y+3)+5(y+3)}$
=$\frac{(y+3)(a+2)}{(y+3)(a+5)}$
=$\frac{(a+2)}{(a+5)}$
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