Answer
$\frac{(y-2)}{4}$
Work Step by Step
$\frac{y^{2}-5y+6}{2y+4}\times\frac{y+2}{2y-6}$
=$\frac{y^{2}-2y-3y+6}{2(y+2)}\times\frac{y+2}{2(y-3)}$
=$\frac{y(y-2)-3(y-2)}{2(1)}\times\frac{1}{2(y-3)}$
=$\frac{(y-2)(y-3)}{2(1)}\times\frac{1}{2(y-3)}$
=$\frac{(y-2)}{2(1)}\times\frac{1}{2}$
=$\frac{(y-2)}{4}$
