Answer
The solutions are -5 and 2
Work Step by Step
2+$\frac{10}{x}$=x+5
x(2+$\frac{10}{x}$)=x(x+5)
2x+10=$x^{2}$+5x
0=$x^{2}$+5x-2x-10
0=x(x+5)-2(x+5)
0=(x-2)(x+5)
x-2=0 or x+5=0
x=2 or x=-5
The solutions are -5 and 2
Check
Let x=2
2+$\frac{10}{x}$=x+5
2+$\frac{10}{2}$=2+5
2+5=7
7=7
Let x=-5
2+$\frac{10}{x}$=x+5
2+$\frac{10}{-5}$=-5+5
2+(-2)=0
0=0
