Answer
$\frac{x(7x-10)}{(x+2)^2(x-2)}$
Work Step by Step
$\frac{6x}{x^2+4x+4}+\frac{x}{x^2-4}$
$\frac{6x}{(x+2)(x+2)}+\frac{x}{(x+2)(x-2)}$
$\frac{6x(x-2)}{(x+2)(x+2)(x-2)}+\frac{x(x+2)}{(x+2)(x-2)(x+2)}$
$\frac{6x(x-2)+x(x+2)}{(x+2)(x+2)(x-2)}$
$\frac{6x^2-12x+x^2+2x}{(x+2)(x+2)(x-2)}$
$\frac{7x^2-10x}{(x+2)(x+2)(x-2)}$
$\frac{x(7x-10)}{(x+2)^2(x-2)}$
