Answer
$\frac{16-3x^2}{4x(3x+2)}$
Work Step by Step
$\frac{4}{3x^2+2x}-\frac{3x}{12x+8}$
$\frac{4}{x(3x+2)}-\frac{3x}{4(3x+2)}$
$\frac{4*4}{4*x(3x+2)}-\frac{3x*x}{4*x(3x+2)}$
$\frac{16}{4x(3x+2)}-\frac{3x^2}{4x(3x+2)}$
$\frac{16-3x^2}{4x(3x+2)}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Practice - Page 513: 6
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