## Algebra: A Combined Approach (4th Edition)

$\frac{1}{21}$$\div$$\frac{6}{14}$
Find the value of for each replacement value. $\frac{x - 3}{5x + 1}$ a. x = 4 b. x = -3 //Simply plug in the variables A. $\frac{4-3}{5(4)+1}$ $\frac{1}{21}$ B. $\frac{-3-3}{5(-3)+1}$ $\frac{6}{14}$ /// the negatives cancel out