Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Cumulative Review: 50

Answer

$x=4$ or $x=9$

Work Step by Step

$x^{2}-13x=-36$ Adding $36$ to both sides, $x^{2}-13x+36=-36+36$. Simplifying, $x^{2}-13x+36=0$. $x^{2}-4x-9x+36=0$ $x(x-4)-9(x-4)=0$ $(x-4)(x-9)=0$ $(x-4)=0$ or $(x-9)=0$ $x=4$ or $x=9$
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