Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 64

Answer

$\dfrac{x^{3}-6x^{2}+9x}{x^{2}+4x-21}=\dfrac{x(x-3)}{x+7}$

Work Step by Step

$\dfrac{x^{3}-6x^{2}+9x}{x^{2}+4x-21}$ Take out common factor $x$ from the numerator and factor the denominator: $\dfrac{x^{3}-6x^{2}+9x}{x^{2}+4x-21}=\dfrac{x(x^{2}-6x+9)}{(x+7)(x-3)}=...$ Factor the parentheses in the numerator and simplify: $...=\dfrac{x(x-3)^{2}}{(x+7)(x-3)}=\dfrac{x(x-3)}{x+7}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.