Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 61

Answer

$\dfrac{3-\dfrac{1}{y}}{2-\dfrac{1}{y}}=\dfrac{3y-1}{2y-1}$

Work Step by Step

$\dfrac{3-\dfrac{1}{y}}{2-\dfrac{1}{y}}$ Evaluate the substractions indicated in the numerator and in the denominator: $\dfrac{3-\dfrac{1}{y}}{2-\dfrac{1}{y}}=\dfrac{\dfrac{3y-1}{y}}{\dfrac{2y-1}{y}}=...$ Evaluate the division and simplify if possible: $...=\dfrac{3y-1}{y}\div\dfrac{2y-1}{y}=\dfrac{y(3y-1)}{y(2y-1)}=\dfrac{3y-1}{2y-1}$
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