# Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set: 53

(2x+1+z)(2x+1-z)

#### Work Step by Step

4$x^{2}$+4x+1-$z^{2}$=($(2x)^{2}$-2*x*1+$1^{2}$)-$z^{2}$= $(2x+1)^{2}$-$z^{2}$=(2x+1+z)(2x+1-z)

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.