Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set: 15

Answer

$(4a-3)^{2}$

Work Step by Step

16$a^{2}$-24a+9=$(4a)^{2}$ -(2)(4a)(3)+$3^{2}$=$(4a-3)^{2}$
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