Answer
$x =- \frac{7}{2}$ or $x=4$
Work Step by Step
$2x^2 - x - 28 = 0$
$2x^2 - 8x + 7x - 28 = 0$
$2x(x - 4) + 7(x - 4) = 0$
$(2x+7) (x-4) = 0$
Therefore
$2x + 7 = 0$ or $x- 4 =0$
$2x = -7$ or $x=4$
$x =- \frac{7}{2}$ or $x=4$
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