Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Review: 90

Answer

The solutions are -3 and 5.

Work Step by Step

$x^{2}$-2x=15 $x^{2}$-2x-15=15-15 $x^{2}$-2x-15=0 $x^{2}$+3x-5x-15=0 x(x+3)-5(x+3)=0 (x-5)(x+3)=0 x-5=0 or x+3=0 x-5+5=0+5 or x+3-3=0-3 x=5 or x=-3 The solutions are -3 and 5. Check Let x=-3 Let $x^{2}$-2x=15 $(-3)^{2}$-2(-3)=15 9+6=15 15=15 Let x=5 $x^{2}$-2x=15 $5^{2}$-2*5=15 25-10=15 15=15
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