Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 19

Answer

$\frac{32}{5}$

Work Step by Step

We are asked to evaluate $\frac{2z^{4}}{5}$ when $z=-2$. We can plug in the given value directly and evaluate. $\frac{2z^{4}}{5}=\frac{2\times(-2)^{4}}{5}=\frac{2\times16}{5}=\frac{32}{5}$
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