Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set - Page 343: 17

Answer

150

Work Step by Step

We are asked to evaluate $2xy^{2}$ when $x=3$ and $y=-5$. We can plug in the given value directly and evaluate. $2xy^{2}=2\times3\times(-5)^{2}=6\times(-5\times-5)=6\times25=150$
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