Algebra: A Combined Approach (4th Edition)

$10^{1.3}$, $19.9526$
Based on the definition of the common logarithm, we know that $log(x)=log_{10}x$. Furthermore, recall that $log_{b}x=y$ is equivalent to the statement $b^{y}=x$ (where $x\gt0$, $y$ is a real number, and $b\gt0$ and $b\ne1$). Therefore, $log(x)=log_{10}x=1.3$ is equivalent to $10^{1.3}=x$. We know that $x=10^{1.3}\approx19.9526$.