Answer
$e^{2.1}$, $4.0552$
Work Step by Step
Based on the definition of the natural logarithm, we know that $ln(x)=log_{e}x$.
Furthermore, recall that $log_{b}x=y$ is equivalent to the statement $b^{y}=x$ (where $x\gt0$, $y$ is a real number, and $b\gt0$ and $b\ne1$).
Therefore, $ln(x)=log_{e}x=2.1$ is equivalent to $e^{2.1}=x$.
We know that $x=e^{2.1}\approx4.0552$.