Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 889: 34

Answer

$e^{2.1}$, $4.0552$

Work Step by Step

Based on the definition of the natural logarithm, we know that $ln(x)=log_{e}x$. Furthermore, recall that $log_{b}x=y$ is equivalent to the statement $b^{y}=x$ (where $x\gt0$, $y$ is a real number, and $b\gt0$ and $b\ne1$). Therefore, $ln(x)=log_{e}x=2.1$ is equivalent to $e^{2.1}=x$. We know that $x=e^{2.1}\approx4.0552$.
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