Answer
$log_{6}(x^{2}+x)$
Work Step by Step
We know that $log_{b}xy=log_{b}x+log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{6}x+log_{6}(x+1)=log_{6}(x\times (x+1))=log_{6}(x^{2}+x)$.
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