## Algebra: A Combined Approach (4th Edition)

$log_{3}\frac{12}{z}$
$\div$We know that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$). Therefore, $log_{3}12-log_{3}z=log_{3}\frac{12}{z}$.