Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Integrated Review - Summary on Solving Quadratic Equations: 22

Answer

$x_{1} = \sqrt{31}$ and $x_{2} = -\sqrt{31}$

Work Step by Step

Given \begin{gather*} x^2-31=0 \end{gather*} Applying difference of two squares, we have: \begin{gather*} (x+\sqrt{31})(x-\sqrt{31})=0 \end{gather*} Therefore the solutions are $x_{1} = \sqrt{31}$ and $x_{2} = -\sqrt{31}$
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