Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Integrated Review - Summary on Solving Quadratic Equations - Page 792: 30

Answer

$x=10\sqrt2$ ft 14.1 ft

Work Step by Step

$x^2+x^2=20^2$ $2x^2=400$ $2x^2/2=400/2$ $x^2=200$ $\sqrt{x^2} =\sqrt{200}$ We want only the positive square root since we are talking about distance. $x=\sqrt {200}$ $x=\sqrt{2∗10∗10}$ $x=10\sqrt2$
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