Answer
$(z+2)(z-2)(z+3)(z-3)$
Work Step by Step
Step 1: Let $u=z^{2}$
$=u^{2}-13u+36$
Step 2: Factor $u^{2}-13u+36$
$=(u-4)(u-9)$
Step 3: Substitute back $u=z^2$
$=(z^{2}-4)(z^{2}-9)$
Step 4: Factor $z^{2}-4$
$=(z+2)(z-2)(z^{2}-9)$
Step 5: Factor $z^{2}-9$
$=(z+2)(z-2)(z+3)(z-3)$