Answer
$p=-12, 1$
Work Step by Step
$p^2+11p-12=0$
$p^2+12p-p-12=0$
$(p^2+12p)+(-p-12)=0$
$p(p+12)-1(p+12)=0$
$(p-1)(p+12)=0$
$p-1=0$
$p=1$
$p+12=0$
$p=-12$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 779: 78
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