Answer
$(2\sqrt{7}+3\sqrt{5})(\sqrt{7}-2\sqrt{5})=-16-\sqrt{35}$
Work Step by Step
$(2\sqrt{7}+3\sqrt{5})(\sqrt{7}-2\sqrt{5})$
Evaluate the product:
$(2\sqrt{7}+3\sqrt{5})(\sqrt{7}-2\sqrt{5})=2\sqrt{7^{2}}-4\sqrt{35}+3\sqrt{35}-6\sqrt{5^{2}}=...$
$...=2(7)-4\sqrt{35}+3\sqrt{35}-6(5)=...$
$...=14-4\sqrt{35}+3\sqrt{35}-30=...$
Simplify by combining like terms:
$...=(14-30)+(3-4)\sqrt{35}=-16-\sqrt{35}$
