Answer
$\dfrac{\sqrt[3]{y^{5}}}{8}+\dfrac{5y\sqrt[3]{y^{2}}}{4}=\dfrac{11y\sqrt[3]{y^{2}}}{8}$
Work Step by Step
$\dfrac{\sqrt[3]{y^{5}}}{8}+\dfrac{5y\sqrt[3]{y^{2}}}{4}$
Simplify the first term:
$\dfrac{\sqrt[3]{y^{5}}}{8}+\dfrac{5y\sqrt[3]{y^{2}}}{4}=\dfrac{y\sqrt[3]{y^{2}}}{8}+\dfrac{5y\sqrt[3]{y^{2}}}{4}=...$
Evaluate the sum and simplify if possible:
$...=\Big[\dfrac{y+10y}{8}\Big]\sqrt[3]{y^{2}}=\dfrac{11y}{8}\sqrt[3]{y^{2}}=\dfrac{11y\sqrt[3]{y^{2}}}{8}$
