Answer
$2y^3\sqrt[3] {5y}$
Work Step by Step
$\sqrt[3] {40y^1}{^0}=\sqrt[3] {8y^9}\sqrt[3]{ 5y}=2y^3\sqrt[3] {5y}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Exercise Set - Page 703: 52
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