Answer
$\dfrac{\sqrt[5]{64x^{10}y^{3}}}{\sqrt[5]{2x^{3}y^{-7}}}=2xy^{2}\sqrt[5]{x^{2}}$
Work Step by Step
$\dfrac{\sqrt[5]{64x^{10}y^{3}}}{\sqrt[5]{2x^{3}y^{-7}}}$
Rewrite this expression as $\sqrt[5]{\dfrac{64x^{10}y^{3}}{2x^{3}y^{-7}}}$ and evaluate the division inside the root:
$\dfrac{\sqrt[5]{64x^{10}y^{3}}}{\sqrt[5]{2x^{3}y^{-7}}}=\sqrt[5]{\dfrac{64x^{10}y^{3}}{2x^{3}y^{-7}}}=\sqrt[5]{32x^{10-3}y^{3+7}}=\sqrt[5]{32x^{7}y^{10}}=...$
Simplify:
$...=2xy^{2}\sqrt[5]{x^{2}}$
