Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Exercise Set: 1

Answer

$\sqrt{7}\cdot \sqrt{2} = \sqrt{14}$

Work Step by Step

$\sqrt{7}\cdot \sqrt{2} = \sqrt{7 \cdot 2} = \sqrt{14}$
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