Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.3 - Simplifying Radical Expressions - Exercise Set: 23

Answer

$\sqrt[3]{\dfrac{2x}{27y^{12}}}=\dfrac{\sqrt[3]{2x}}{3y^{4}}$

Work Step by Step

$\sqrt[3]{\dfrac{2x}{27y^{12}}}$ Take the cubic root of both the numerator and the denominator and simplify: $\sqrt[3]{\dfrac{2x}{27y^{12}}}=\dfrac{\sqrt[3]{2x}}{\sqrt[3]{27y^{12}}}=\dfrac{\sqrt[3]{2x}}{3y^{4}}$
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