Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.2 - Rational Exponents - Exercise Set: 60

Answer

$\dfrac{(a^{-2}b^{3})^{1/8}}{(a^{-3}b)^{-1/4}}=\dfrac{b^{5/8}}{a}$

Work Step by Step

$\dfrac{(a^{-2}b^{3})^{1/8}}{(a^{-3}b)^{-1/4}}$ Evaluate the powers indicated in the numerator and in the denominator: $\dfrac{(a^{-2}b^{3})^{1/8}}{(a^{-3}b)^{-1/4}}=\dfrac{a^{-1/4}b^{3/8}}{a^{3/4}b^{-1/4}}=...$ Evaluate the division. Give the answer without negative exponents: $...=a^{-1/4-3/4}b^{3/8+1/4}=a^{-1}b^{5/8}=\dfrac{b^{5/8}}{a}$
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