Answer
$\dfrac{(m^{2}n)^{1/4}}{m^{-1/2}n^{5/8}}=\dfrac{m}{n^{3/8}}$
Work Step by Step
$\dfrac{(m^{2}n)^{1/4}}{m^{-1/2}n^{5/8}}$
Evaluate the power indicated in the numerator:
$\dfrac{(m^{2}n)^{1/4}}{m^{-1/2}n^{5/8}}=\dfrac{m^{1/2}n^{1/4}}{m^{-1/2}n^{5/8}}=...$
Evaluate the division. Give the answer without negative exponents:
$...=m^{1/2+1/2}n^{1/4-5/8}=mn^{-3/8}=\dfrac{m}{n^{3/8}}$
