## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 10 - Section 10.1 - Radical Expressions and Radical Functions - Practice: 28

#### Answer

$6x$

#### Work Step by Step

Using the rule given in the book: If $n$ is an even positive integer, then $\sqrt[n]{a^n} = |a|$ If $n$ is an odd positive integer, then $\sqrt[n]{a^n} = a$ We get $\sqrt{36x^2} = \sqrt{(6x)^2} \rightarrow |6x| = 6x$

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