Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.1 - Radical Expressions and Radical Functions - Practice - Page 683: 29

Answer

$x+3$

Work Step by Step

Using the rule given in the book: If $n$ is an even positive integer, then $\sqrt[n]{a^n} = |a|$ If $n$ is an odd positive integer, then $\sqrt[n]{a^n} = a$ We get $\sqrt{x^2+6x+9} = \sqrt{(x+3)^2} \rightarrow |x+3| = x+3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.